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Code Block
list1 = ['physics', 'chemistry', 1997, 2000];
list2 = [1, 2, 3, 4, 5 ];
list3 = ["a", "b", "c", "d"]

Tuple

Info

The tuples cannot be changed unlike lists and tuples use parentheses, whereas lists use square brackets.

Code Block
tup1 = ('physics', 'chemistry', 1997, 2000);
tup2 = (1, 2, 3, 4, 5 );
tup3 = "a", "b", "c", "d";

Set

Info

Unordered collections of unique elements

Code Block
Set(['Jane', 'Marvin', 'Janice', 'John', 'Jack'])
Set(['Janice', 'Jack', 'Sam'])
Set(['Jane', 'Zack', 'Jack'])
Set(['Jack', 'Sam', 'Jane', 'Marvin', 'Janice', 'John', 'Zack'])

Dictionary

Info

Keys are unique within a dictionary while values may not be. The values of a dictionary can be of any type, but the keys must be of an immutable data type such as strings, numbers, or tuples.

Code Block
dict = {'Name': 'Zara', 'Age': 7, 'Class': 'First'}

Get last name from full name by split()

The function can be easily implemented by string method

Code Block
actor = {"name": "John Cleese", "rank": "awesome"}

def get_last_name():
    return actor["name"].split()[1]

get_last_name()
print("All exceptions caught! Good job!")
print("The actor's last name is %s" % get_last_name())

Split string as list

Code Block
sentence = "the quick brown fox jumps over the lazy dog"
words = sentence.split()
print(words)

Filter positive numbers only - 1

Code Block
numbers = [34.6, -203.4, 44.9, 68.3, -12.2, 44.6, 12.7]
newlist = []
for number in numbers:
    if number>0:
        newlist.append(number)
print(newlist)

Filter positive numbers only - 2

Code Block
numbers = [34.6, -203.4, 44.9, 68.3, -12.2, 44.6, 12.7]
newlist = [int(x) for x in numbers if x > 0]
print(newlist)

Create word list from a sentence with no duplicate entries

set() removes all the duplicate entries in the array

Code Block
strings = "my name is Chun Kang and Chun is my name"
r = set(strings.split())
print(r)

...


Split string as list

Code Block
sentence = "the quick brown fox jumps over the lazy dog"
words = sentence.split()
print(words)


Filter positive numbers only - 1

Code Block
numbers = [34.6, -203.4, 44.9, 68.3, -12.2, 44.6, 12.7]
newlist = []
for number in numbers:
    if number>0:
        newlist.append(number)
print(newlist)


Filter positive numbers only - 2

Code Block
numbers = [34.6, -203.4, 44.9, 68.3, -12.2, 44.6, 12.7]
newlist = [int(x) for x in numbers if x > 0]
print(newlist)


Create word list from a sentence with no duplicate entries

set() removes all the duplicate entries in the array

Code Block
strings = "my name is Chun Kang and Chun is my name"
r = set(strings.split())
print(r)


Tuple

Info

The tuples cannot be changed unlike lists and tuples use parentheses, whereas lists use square brackets.


Code Block
tup1 = ('physics', 'chemistry', 1997, 2000);
tup2 = (1, 2, 3, 4, 5 );
tup3 = "a", "b", "c", "d";


Set

Info

Unordered collections of unique elements


Code Block
Set(['Jane', 'Marvin', 'Janice', 'John', 'Jack'])
Set(['Janice', 'Jack', 'Sam'])
Set(['Jane', 'Zack', 'Jack'])
Set(['Jack', 'Sam', 'Jane', 'Marvin', 'Janice', 'John', 'Zack'])

Find overlapped entries from two arrays

Code Block
a = set([ "Seoul", "Pusan", "Incheon", "Mokpo" ])
b = set([ "Seoul", "Incheon", "Suwon", "Daejeon", "Gwangjoo", "Taeku"])

print(a.intersection(b))
print(b.intersection(a))

The result will be like below

Result 

{'Seoul', 'Incheon'}

{'Seoul', 'Incheon'}


Find different elements from two arrays based on "symmetric_difference" method

Code Block
a = set([ "Seoul", "Pusan"Jake", "IncheonJohn", "MokpoEric" ])
b = set([ "SeoulJohn", "Incheon", "Suwon", "Daejeon", "Gwangjoo", "Taeku"Jill"])

print(a.intersectionsymmetric_difference(b))
print(b.intersectionsymmetric_difference(a))

The result will be like below

Result 

{'Jake'

Seoul

, 'Eric', '

Incheon

Jill'}

{'Eric', '

Seoul

Jake', '

Incheon

Jill'}


Find different elements from two arrays based on "

...

difference" method

Code Block
a = set(["Jake", "John", "Eric"])
b = set(["John", "Jill"])

print(a.symmetric_difference(b))
print(b.symmetric_difference(a))

The result will be like below

Result 

{'Jake', 'Eric

', 'Jill

'}

{

'Eric',

'

Jake', '

Jill'}


Find different elements from two arrays based on "

...

union" method

Code Block
a = set(["Jake", "John", "Eric"])
b = set(["John", "Jill"])

print(a.differenceunion(b))
print(b.difference(a))

The result will be like below

Result 

{'

Jake

John', 'Eric', '

Eric

Jake'

}{

, 'Jill'}

...


Print out a set containing all the participants from event A which did not attend event B

Code Block
a = set(["Jake", "John", "Eric"])
b = set(["John", "Jill"])

print(a.union(b))

The result will be like below

...

{'John', 'Eric', 'Jake', 'Jill'}

(set(a).difference(set(b)))


Dictionary

Info

Keys are unique within a dictionary while values may not be. The values of a dictionary can be of any type, but the keys must be of an immutable data type such as strings, numbers, or tuples.


Code Block
dict = {'Name': 'Zara', 'Age': 7, 'Class': 'First'}


Get last name from full name by split()

The function can be easily implemented by string method

Code Block
actor = {"name": "John Cleese", "rank": "awesome"}

def get_last_name():
    return actor["name"].split()[1]

get_last_name()
print("All exceptions caught! Good job!")
print("The actor's last name is %s" % get_last_name(

Print out a set containing all the participants from event A which did not attend event B

Code Block
a = ["Jake", "John", "Eric"]
b = ["John", "Jill"]

print(set(a).difference(set(b)))



Generator

Random number generation

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